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Dynamic memory re-allocation in C Language using realloc() function
Mar 06, 2022   Vikas Suhag

#include <stdio.h>
#include <stdlib.h>
int main()
{
int* ptr;     // This pointer will hold the
int n, i;    // Get the number of elements for the array
n = 5;
ptr = (int*)calloc(n, sizeof(int));

if (ptr == NULL) {
printf("Memory not allocated.\n");
exit(0);
}
else  // Memory has been successfully allocated
    {
    printf("Memory successfully allocated using calloc.\n");
    
    for (i = 0; i < n; ++i) // Get the elements of the array
    {     
    ptr[i] = i + 1;     
    }
    
    // Print the elements of the array
    printf("The elements of the array are: ");
    for (i = 0; i < n; ++i) {
    
    printf("%d, ", ptr[i]);
    }
    // Get the new size for the array
    n = 10;
    printf("\n\nEnter the new size of the array: %d\n", n); // Dynamically re-allocate memory using realloc()
    ptr = (int*)realloc(ptr, n * sizeof(int)); // Memory has been successfully allocated
    printf("Memory successfully re-allocated using realloc.\n"); // Get the new elements of the array
    for (i = 5; i < n; ++i) {
    ptr[i] = i + 1;
    } // Print the elements of the array
    printf("The elements of the array are: ");
    for (i = 0; i < n; ++i) {
    printf("%d, ", ptr[i]);
    }
    free(ptr);
    }
return 0;
}


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